14b^2+106b-180=0

Solution for 14b^2+106b-180=0 equation:

14b^2+106b-180=0

a = 14; b = 106; c = -180;
Δ = b2-4ac
Δ = 1062-4·14·(-180)
Δ = 21316
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{21316}=146$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(106)-146}{2*14}=\frac{-252}{28}
=-9
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(106)+146}{2*14}=\frac{40}{28}
=1+3/7
$